2[d-(4d+13)+11]=2(d+2)

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Solution for 2[d-(4d+13)+11]=2(d+2) equation:


Simplifying
2[d + -1(4d + 13) + 11] = 2(d + 2)

Reorder the terms:
2[d + -1(13 + 4d) + 11] = 2(d + 2)
2[d + (13 * -1 + 4d * -1) + 11] = 2(d + 2)
2[d + (-13 + -4d) + 11] = 2(d + 2)

Reorder the terms:
2[-13 + 11 + d + -4d] = 2(d + 2)

Combine like terms: -13 + 11 = -2
2[-2 + d + -4d] = 2(d + 2)

Combine like terms: d + -4d = -3d
2[-2 + -3d] = 2(d + 2)
[-2 * 2 + -3d * 2] = 2(d + 2)
[-4 + -6d] = 2(d + 2)

Reorder the terms:
-4 + -6d = 2(2 + d)
-4 + -6d = (2 * 2 + d * 2)
-4 + -6d = (4 + 2d)

Solving
-4 + -6d = 4 + 2d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2d' to each side of the equation.
-4 + -6d + -2d = 4 + 2d + -2d

Combine like terms: -6d + -2d = -8d
-4 + -8d = 4 + 2d + -2d

Combine like terms: 2d + -2d = 0
-4 + -8d = 4 + 0
-4 + -8d = 4

Add '4' to each side of the equation.
-4 + 4 + -8d = 4 + 4

Combine like terms: -4 + 4 = 0
0 + -8d = 4 + 4
-8d = 4 + 4

Combine like terms: 4 + 4 = 8
-8d = 8

Divide each side by '-8'.
d = -1

Simplifying
d = -1

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